Tokyo/Hill function fitting

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(Deviation of Hill function)
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'''1.Hill function for the activator AHL'''  
'''1.Hill function for the activator AHL'''  
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[[Image:hill-fitting-1.jpg|200px|right|thumb|Figure 1]]
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[[Image:hill-fitting-1.jpg|200px|right|thumb|'''Fig. 1''' AHL absorbed in a cell binds to LuxR to make a complex, which activates the lax lac hybrid promoter and expression of GFP downstream of it. In this way, a cell recieves AHL as an input and gives off green fluorescence as its output. ]]
Without the repression by LacI( [LacI]=0 ), Ex.6.1 was described as  
Without the repression by LacI( [LacI]=0 ), Ex.6.1 was described as  
<br>[[Image:expression6-4.JPG|300px|none|thumb|Ex.6.2]]
<br>[[Image:expression6-4.JPG|300px|none|thumb|Ex.6.2]]

Revision as of 13:34, 25 October 2007


Works top  0.Hybrid promoter  1.Formulation  2.Assay1  3.Simulation  4.Assay2  5.Future works

Purpose of this assay  1.AHL assay  2.IPTG assay  Preliminary assays


Purpose:


We have conducted the assays to obtain parameters in the Hill function expressing our model.

The how the hill function is deviated is described below.

Deviation of Hill function


Ex.6.1


1.Hill function for the activator AHL

Fig. 1 AHL absorbed in a cell binds to LuxR to make a complex, which activates the lax lac hybrid promoter and expression of GFP downstream of it. In this way, a cell recieves AHL as an input and gives off green fluorescence as its output.

Without the repression by LacI( [LacI]=0 ), Ex.6.1 was described as


Ex.6.2

Therefore, in the steady state the Hill function for the activator AHL was given as

Ex.6.3
Ex.6.4

2.Hill function for the repressor LacI

Figure 2

When the concentration of AHL was assumed to be infinity, Ex.6.1 was described as


Ex.6.5

Therefore, in the steady state the Hill function for the repressor LacI was given as


Ex.6.6

Ex.6.7


However, the amount of LacI cannot be actually measured.So,we used the inducer IPTG to calculate the Hill function for LacI.
Assume that the reaction between [LacI] and [IPTG] is the equilibrium reaction,these concentration in equilibrium state were shown in Fig.3.


Figure 3

Therefore,the equilibrium constant k0 was obtained as


Ex.6.8

Moreover, assume that [IPTG]_total was more than [LacI=IPTG] predominantly,


Ex.6.9

By substituting Ex.6.9 into Ex.6.8, [LacI] was obtained as


Ex.6.10

As a result, by substituting Ex.6.10 into Ex.6.7,the Hill function for LacI was obtained as the function of [IPTG]total,


Ex.6.11

Here k0=0.0337(/μM),[LacI]total=140(μM).