Tokyo/IPTG assay

From 2007.igem.org

Revision as of 02:45, 27 October 2007 by Kiga (Talk | contribs)


Works top   0.Hybrid promoter   1.Formulation   2.Assay1   3.Simulation   4.Assay2   5.Future works

Objective of this assay   Effect of AHL   Effect of LacI-IPTG  Preliminary assays


LacI-IPTG assay

Objective:


By testing how LacI represses lux-lac hybrid promoter, parameters(n3,K3) should be decided. In order to adjust effective concentration of LacI, IPTG was added.
The order of the concentration is used for more detailed assay with narrower range of the IPTG concentration.

Samples:

in DH5 alpha
A4 pcI([http://partsregistry.org/Part:BBa_I751103 BBa_I751103]) into pTrc99A cell (LacI producing cell)
A4 ΔP([http://partsregistry.org/Part:BBa_I751100 BBa_I751100]) into pTrc99A cell (LacI producing cell)
A4 ΔP + Lux-lac hybrid promter ([http://partsregistry.org/Part:BBa_I751101 BBa_I751101]) into pBR322 cell (LacI non-producing cell)
A4 ΔP + Lux-lac hybrid promter ([http://partsregistry.org/Part:BBa_I751101 BBa_I751101]) into pTrc99A cell (LacI producing cell)

Procedure:

Fig.1: As more IPTG is exogenously (externally) added, the fluorescence becomes more intense in the presence of AHL.


prepare overnight culture for each sample
make fresh culture
take 3 ul of the overinight culture into 3 ml of LB (Amp and/or Kan) in Falcon tubes.
incubate for 2 to 3 hours until the observed OD is around 0.5
add AHL & IPTG solution
[AHL]final (in 3 ml LB culture) = 10 nM
[IPTG]final (in 3 ml LB culture) = 1000, 100, 10, 1, 0.1, 0.01, and 0 mM
incubate for 2 to 3 hours
apply 150 ul of samples into 96-well plaste
FLA measurement

Result & Conclusion:

Fig.2: Fluorescence intensity as a function of the concentration of IPTG was determined.

As the concentration of IPTG increases, GFP fluorescence increased, indicating that the hybrid promoter in the LacI expressing cell became increasingly strengthened by decreasing repression by LacI. The activation graph in Fig. 2, the characteristics of the hybrid promoter expressed in Hill function is determined.


n3 = 2.47 (-)
K3 = 0.295 (μM)